Question

please can you give me answer

Answer 1

Volume of barrel = πR^2×H = π×20×20×50

Volume of mug = πr'^2h' = π×5×5×10

Number of mugs required = Volume Barrel/ Volume of Mug

N ==== π×20×20×50 /π×5×5×10

N======4×4×5

N=======80

So number of mugs required is 80.

Answer 2

$volume \: of \: barrel = \pi \times {r}^{2} \times h$
=
$3.14 \times 20 \times 20 \times 50$
$volume \: of \: mug = \pi {r}^{2} \times h$
$= 3.14 \times 5 \times 5 \times 15$
minimum mugs required=
$\frac{volume \: of \: barrel}{volume \: of \: mug}$
$= \frac{3.14 \times 20 \times 20 \times 50}{3.14 \times 5 \times 5 \times 15}$
$approx = 53$