Question

please can you help me in this one​

Answer 1

Step-by-step explanation:

tan 1 . tan 2 . tan 3 … tan (90 – 3 ) . tan ( 90 – 2 ) . tan ( 90 – 1) 

tan 1 . tan 2  . tan 3 … cot 3 . cot 2 . cot 1 

tan 1 . cot 1 . tan 2 . cot 2 . tan 3 . cot 3 … tan 89 . cot 89

We know that tanA.cotA=1

1 x 1 x 1 x 1 x … x 1 

As 1ⁿ = 1 

so , Option C is correct