Question

Please can you solve this as soon as possible

Answer 1

Answer:

$1) \: \: {x}^{2} - 9x + 10 = 0 \\ = {x}^{2} - 6x - 3x + 18 = 0 \\ = x(x - 6) - 3(x - 6) = 0 \\ = (x - 6)(x - 3) = 0 \\ = x = 6 \: \: and \: \: 3 \: \: ans \: \\ 2) \: {y}^{2} + 18y + 17 = 0 \\ = {y}^{2} + 17y + y + 17 = 0 \\ = y(y + 17) + 1(y + 17) = 0 \\ = (y + 17)(y + 1) = 0 \\ = y = - 17 \: \: and \: \: - 1 \: \: ans \\ \\ 3)3 {x}^{2} - x - 10 = 0 \\ = 3 {x}^{2} - 6x + 5x - 10 = 0 \\ = 3x(x - 2) + 5(x - 2) = 0 \\ = (x - 2)(3x + 5) = 0 \\ = x = \frac{ - 5}{3} \: \: and \: \: 2 \: \: ans \\ \\ 4)5a {}^{2} - 7a - 6 = 0 \\ = 5 {a}^{2} - 10a + 3a - 6 = 0 \\ = 5a(a - 2) + 3(a - 2) = 0 \\ = (a - 2)((5a + 3) = 0 \\ = a = 2 \: \: and \: \: \frac{ - 3}{5} \: \: ans \\ \\ 5) \: 12 {x}^{2} - 10x + 2 = 0 \\ = 12 {x}^{2} - 6x - 4x + 2 = 0 \\ = 3x(x - 2) - 2(2x - 1) = 0 \\ = (2x - 1)(3x - 2) = 0 \\ = x = \frac{1}{2} \: \: and \: \: \frac{2}{3} \: \: ans$

Hey! Mate Here is your solution.

Please mark this brainliest ans thanks