Question

please check attachment​

Answer 1

Step-by-step explanation:

Let the value of helmet be x

x + x + x = 36

x = 12

Let the value of bag be y

y + x + y = 20

2y = 8

y = 4

Let the value of flare gun be z

y + z + z = 10

2z = 6

z = 3

so

x + y + z

12 + 4 + 3

21

#answerwithquality #BAL

Answer 2

$\huge\boxed{\fcolorbox{blue}{grey}{Answer}} : = > \\ \\ \large \: \: we \: \: can \: \: assume \: \: = > helmet \: \: = x \\ \\ \large \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > bag = y \\ \\ \large \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > gun = z \\ \\ so \: \: first \: \: . \: \: \: x + x + x = 36 \\ \\ 3x = 36 \\ \\ x = \frac{36}{3} \\ \\ x = 12 \\ \\ in \: \: second \: \: case \: \: . \: \: y + x + y = 20 \\ \\ y + 12 + y = 20 \\ \\ 2y + 12 = 20 \\ \\ 2y = 20 - 12 \\ \\ 2y = 8 \\ \\ y = \frac{8}{2} \\ \\ y = 4 \\ \\ in \: \: third \: \: case \: \: . \: \: y + z + z = 10 \\ \\ 4 + 2z = 10 \\ \\ 2z = 6 \\ \\ z = \frac{6}{2} z = 3 \\ \\ so \: \: now \: \: for \: \: last \: \: case \: . \: \: x - y \times z \\ \\ = 12 - 4 \times 3 \: \\ \\ = 12 - 12 \: \: \: \: \: \: \: \:\\ \\ = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

so I hope this will be help you

and I'm also from Ahmedabad..xD