Question

please check attachment and choose correct option for that...​

Answer 1

Answer:

Q1.)=Factors=(x-2) (x+2)

Q2.)=Factors=(3-7a) (3+7a)

Q3.)=Factors=(5x-1) (5x+1)

Q4.)=Factors=(ab-6) (ab+6)

Q5.)=Factors=(a+b) (a-b)

Step-by-step explanation:

Q1.)=Here, As per our given question,

=x^2-4=0

=x^2-(2)^2

Here, The identity which is used is:(a^2-b^2=(a+b) (a-b),

=(x+2) (x-2)

=x+2=0, x-2=0

=x=(-2) and x=2

Hence factors of this given equation are:(x+2) (x-2).

Q2.)=9-49a^2

=(3)^2-(7a)^2

Here, The identity which is used is:(a^2-b^2=(a+b) (a-b),

=(3+7a),(3-7a)

=3+7a=0 and 3-7a=0

=7a=(-3) and (-7a)=(-3)

=a=(-3)/7 and 7a=3

and a=3/7.

Hence, The factors of this equation are =(3+7a) (3-7a).

Q3.)=25x^2-1

=(5x)^2-(1)^2

Here, The same identity is used as in previous question,

=(5x+1) (5x-1)

=5x+1=0 and 5x-1=0

=5x=(-1) and 5x=1

=x=(-1)/5 and x=1/5

Hence, The factors of this equation are=(5x+1) (5x-1)

Q4.)=a^2b^2-36

=(a^2b^2)-(6^2)

Here also, The identity is used as per previous question,

=(ab+6) (ab-6)

=ab+6=0 and ab-6=0

=ab=(-6) and ab=6

So, Here, The factors of this equation are =(ab-6) (ab+6)

Q5.)=a^2-b^2

Here, The identity is given which is usedin previous questions,

=(a+b) (a-b)

=a+b=0 and a-b=0

=a=(-b) and a=b

So, The factors of this equation are (a+b) (a-b).

Thank you.

Answer 2

1...c

2..b

3...c

4....a

5..b

hope it's help you