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your answer is in the picture
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pramod52:
Thank you so much
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hey...
1. in triangle AOB , OA and OB are radius of circle...so OA = OB.
OA and OB are also sides of triangle AOB that are equal.
OA = OB (radii of circle.)
angle OBA = angle OAB = 50 degree.
2. in triangle AOC
OC = OA ( radii of circle)
angle OCA = angle OAC = 20 degree.
angle OAB + angle OAC = angle BAC
50 + 20 = 70
by angle subtended theorem
angle BOC = 2 × angle BAC
= 2 × 70
= 140.
1. in triangle AOB , OA and OB are radius of circle...so OA = OB.
OA and OB are also sides of triangle AOB that are equal.
OA = OB (radii of circle.)
angle OBA = angle OAB = 50 degree.
2. in triangle AOC
OC = OA ( radii of circle)
angle OCA = angle OAC = 20 degree.
angle OAB + angle OAC = angle BAC
50 + 20 = 70
by angle subtended theorem
angle BOC = 2 × angle BAC
= 2 × 70
= 140.
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