Question

please copy main solve karke bhej do bohat important hai urgent​

Answer 1

Question -

The length and breadth of a rectangle are (a² + ab + b²) units and (a-b) units respectively. Find the area and perimeter of rectangle.

__________________________

Solution-

✧ Given,

• length of a rectangle = (a² + ab + b²) units
• breadth of a rectangle = (a-b) units

✧ To find,

• the area of rectangle
• the perimeter of rectangle.

✧ Solution,

Area of rectangle = (l × b) units.

where,

l = length & b = breadth (of the rectangle)

Putting the values of l and b (length and breadth)

$\implies\sf{(a² + ab + b²) × (a-b)}$

$\implies\sf{(a² + ab + b²) - b(a² + ab + b²) }$

$\implies\sf{a^3 \cancel{+ a^{2}b} \cancel{+ ab^2} - \cancel{a^{2}b }\cancel{- ab^{2}} - b^{3}}$

${\footnotesize{\therefore{\boxed{\bf{Area\: of\: rectangle => a^3 - b^3units.}}}}}$

Perimeter of rectangle = {2(l + b)} units.

where,

l = length & b = breadth (of the rectangle)

Putting the values of l and b (length and breadth)

$\implies\sf{2\{(a^2 + ab + b^2) + (a-b)\}}$

${\footnotesize{\therefore{\boxed{\bf{Perimeter\: of\: rectangle => \{2(a^2 + ab + b^2 + a - b)\}units.}}}}}$

__________________________

Note:- You may obtain the handwritten solution from the attachment.

__________________________