Question

please correcly answer i will mark you brainlist

Answer 1

Answer:

I think it is 200 Joule....

Explanation:

hope this'll help you

Answer 2

Answer:

Option B = 600 J

Explanation:

Previous Knowledge:

Work-Energy Theorem: It states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.

         Work = Change in KE

Solution:

Given,  m = 100 kg

            u = 2 m/s

            v = 4 m/s

Work Done = Change in KE

                    = $\frac{1}{2} mv^{2} - \frac{1}{2}mu^{2}$

                    = $\frac{1}{2}100 (4)^{2} - \frac{1}{2}100 (2)^{2}$

                    = $\frac{1}{2} 100 [4^{2} - 2^{2}]$

                   =  $\frac{1}{2} 100 (12)$

                   = 600 J

Hence the correct option is B.