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please derive s=ut+1/2at^ graphically method
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from velocity time graph
displacement =area of trapezium OABD
s=1/2(OA+BD) AC
s=1/2(u+v) t. [ since,v=u+at]
s=1/2(u+u+at)t
s=1/2(2u+at)t
s=1/2×2ut+1/2at²
s= ut+1/2at²
proved
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