Question

Please do all questions ;-

No need to show steps .

Answer 1

Hi ,. there !!


here is your answer !!


let ,

@ == alpha


bita == ß




1 ). p ( x ) = 2x² - 5x + 49


@ + ß = - b / a


=> -(5) / 2


=> 5/2 answer



2).


3 is zeroes of polynomial so ,
on putting the value of zeoes in polynomial we get



p ( x ) = x²-3x + p


=> (3)²- 3 × 3 + p = 0



9 - 9 + p = 0


p => 0





3 ) given @ and ß are zeoes


to find @ß

==============

p ( x ) = x² - 3x + 4



@× ß= c / a


=> 4 / 1


=> 4



4 ) @ and ß are zeoes ,



to find @+ ß


p ( x ) = 3x² - 4 x + 2


=> @+ ß= - b / a


=> -(-4) / 3


=> 4 / 3




5 ) find

f ( 4 )


f ( x ) = 3x + 5


on putting the value of f ( 4 ) in f ( x )

we get ,


3 ( 4 ) + 5


=> 12 + 5


=> 17


hope it's help you sister !!!





thanks !!!

Answer 2

HEY MATE

Your answer is ---

we know that

sum of roots =$- \frac{coefficient \: \: of \: {x}^{2} }{coefficient \: of \: x}$

1. Given, f(x) = 2x^2 -5x +49

so,
$\alpha + \beta = - (-5)/2 = 5/2 -------------------------------- 2. Given, 3 is the zero of given f(x) = x^2-3x+p so, f(3) = 0 => 3^2 - 3×3 +p = 0 => 9 -9 + p = 0 => p = 0 -------------------------------- 3. Given, p(x) = x^2 -3x +4 we know that product of zeroes = [tex] \frac{constant \: term }{coefficient \: of \: {x}^{2} }$


so,
$\alpha \beta = \frac{4}{1} = 4$

---------------------------------

4. Given, p(x) =3x^2 -4x +2

so,
$\alpha + \beta = - \frac{( - 4)}{3} = \frac{4}{3}$

--------------------------------

5. Given, f(x) = 3x+5

so, f(4) is

= 3×4+5 = 12+5

= 17

____________________________

$\textbf { HOPE IT HELPS YOU }$