Question

please do all the parts and full solution please guys ​

Answer 1

Answer:

4ab(3a-2b)

4×-1×2(3×-1-2×2)

-8(-3-4)

-8×-7

=56

a°(7ab+c)

(-1)(7×-1×2+1)

(-1)(-7×2+1)

(-1)(-14+1)

(-1)(-13)

=13

Answer 2

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$a) \: 4ab(3a - 2b)$

$4 \times ( - 1) \times 2(3 \times ( - 1) - 2 \times ( 2)$

$- 4 \times 2( - 3 \times ( - 4))$

$- 8 \times 12$

$96$

$b) \: {a}^{3} (7ab + c)$

${( - 1)}^{3} (7 \times ( - 1) \times 2 + 1)$

$- 1( - 7 \times 2 + 1)$

$- 1( - 14 + 1)$

$- 1 \times ( - 13)$

$13$

$c) \: (5a - 2b)(3b + 4c)$

$5a(3b + 4c) - 2b(3b + 4c)$

$15ab + 20ac - 6 {b}^{2} - 8ac$

$15ab + 12ac - 6 {b}^{2}$

$15( -1 )(2) + 12( - 1)(1) - 6 {(2)}^{2}$

$15 \times ( - 2) + 12( - 1) - 6 \times 4$

$- 30 - 12 - 24$

$- 30 - 36$

$- 66$

$d) \: [ \frac{1}{2} a - 3b] ^{2}$

$[ \frac{1}{2}a ]^{2} - 2 \times \frac{1}{2} a \times 3b \: + [3b]^{2}$

$\frac{1}{4} {a}^{2} - 3ab \: + 9 {b}^{2}$

$\frac{1}{4} \times ( - 1)^{2} - 3 \times ( - 1) \times 2 + 9 {(2)}^{2}$

$\frac{1}{4} \times 1 + 6 \times 2 + 9 \times 4$

$\frac{1}{4} + 12 + 36$

$\frac{1}{4} + 48$

$\frac{193}{4}$

$48.25$