please do all the parts and full solution please guys and please those will answer who know the solution please...
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Answer:
(7+4
3
)
(5+2
3
)
=a+b
3
\frac{(5 + 2 \sqrt{3})(7 - 4 \sqrt{3}) }{(7 + 4 \sqrt{3} )(7 - 4 \sqrt{3}) } = a + b \sqrt{3}
(7+4
3
)(7−4
3
)
(5+2
3
)(7−4
3
)
=a+b
3
\frac{5(7 - 4 \sqrt{3}) + 2 \sqrt{3}(7 - 4 \sqrt{3} ) }{ {(7)}^{2} - {(4 \sqrt{3} )}^{2} } = a + b \sqrt{3}
(7)
2
−(4
3
)
2
5(7−4
3
)+2
3
(7−4
3
)
=a+b
3
\frac{35 - 20 \sqrt{3} + 14 \sqrt{3} + 18 }{49 - 48} = a + b \sqrt{3}
49−48
35−20
3
+14
3
+18
=a+b
3
\frac{35 + 18 - 6 \sqrt{3} }{1} = a + b \sqrt{3}
1
35+18−6
3
=a+b
3
{53 - 6 \sqrt{3} } = a + b \sqrt{3}53−6
3
=a+b
3
a = 53 \: and \: b = 6a=53andb=6
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