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Step-by-step explanation:
let a2−b2=x1;b2−c2=y1;c2−a2=z1
x1+y1+z1=0
⇒x13+y13+z13=3x1y1z1=3(a2−b2)(b2−c2)(c2−a2)
let a−b=x2;b−c=y2;c−a=z2
x2+y2+z2=0
⇒x23+y23+z23=3x2y2z2=3(a−b)(b−c)(c−a)
So,
x23+y23+z23x13+y13+z13=(a+b)(b+c)(c+a)
THIS IS YOUR ANSWER OKAY
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