Math, asked by Anonymous, 5 months ago

please do answer this question​

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Answered by ravi2303kumar
0

Answer:

(a)\frac{1}{2^{5}*3^{7}}

(b)2^6 * 3^3

Step-by-step explanation:

(a) \frac{2^{-6}*2^{4}*3^{5}} {3^{12}*2^{3}}

    = \frac{2^{-6+4-3}}{3^{12-5}}

    = \frac{2^{-5}}{3^{7}}

    = \frac{1}{2^{5}*3^{7}}

(b) \frac{9^{1}*6^{7}*2^{5}}{8^{2}*3^{6}}

   = \frac{3^{2}*2^{7}*3^{7}*2^{5}}{(2^{3})^{2}*3^{6}}

   = \frac{3^{2+7}*2^{7+5}}{2^{6}*3^{6}}

   = \frac{2^{12}*3^{9}}{2^{6}*3^{6}}

   = 2^{12-6}*3^{9-6}

   = 2^6 * 3^3

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