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Answer:
cos135°-cos 120°)/(cos135°+cos120°)=3–2.2^1/2.
L.H.S.
cos135° =cos (180°-45°)= -cos 45° = -1/2^1/2.
cos120°=cos(180°-60°)= -cos60° = -1/2
=( -1/2^1/2 +1/2)/(-1/2^1/2 - 1/2)
=(1/2^1/2–1/2)/(1/2^1/2+1/2).
=(2^1/2 -1)/(2^1/2+1) , multiply above and below by (2^1/2 -1).
=(2^1/2–1)×(2^1/2–1)/(2^1/2+1)×(2^1/2–1).
=(2+1–2×2^1/2×1)/(2–1)
=(3- 2.2^1/2) , proved
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