Please do D part....its urgent
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Answer:
Let A = 7x + 1
Let B = 5x - 3
Covert the equation in the form :
-> 3A² - 4B² = 11AB
-> 3A² -11AB -4B² = 0
Factorize the middle term.
3A² - 12 AB +AB -4B² = 0
3A(A-4B) + B(A-4B) = 0
(A-4B)(3A+B) = 0
A = 4B or 3A = -B
Again substitute original values , 7x+1 and 5x-3
solve for x we get :
7x +1 = 4(5x -3)
x = 1
or
21x+3 = -5x + 3
x = 0
Substitute in the main equation and check
its correct !
Answered by
2
let (7X+1)/5x-3 =A
3A -(4/A) =11
x= 1 & 0
X =1 satisfies equation
so answer is 1
3A -(4/A) =11
x= 1 & 0
X =1 satisfies equation
so answer is 1
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