Question

please do fast it's urgent​

Answer 1

Answer:

$k = \frac{4}{9}$

Step-by-step explanation:

$one \: root \: is \: - \frac{1}{3} \\ x = - \frac{1}{3}$

Put that x value in given equation

$2 {x}^{2} + 2x + k \\ 2 {( - \frac{1}{3} )}^{2} + 2( - \frac{1}{3} ) + k = 0 \\ \frac{2}{9} - \frac{2}{3} + k = 0 \\ \frac{2 - 6 + 9k}{9} = 0 \\ - 4 + 9k = 0 \\ 9k = 4 \\ k = \frac{4}{9}$

Answer 2

Step-by-step explanation:

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Zero = -1/3

so,

x = -1/3 (putting value of x in equation)

$2( \frac{-1}{9} ) + 2( \frac{-1}{3} ) + k \\ \frac{2}{9} - \frac{2}{3} + k = 0 \\ \frac{4}{9} = - k \\ k = \frac{ -4}{9}$