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the pic is not clear so send it again I'll ans
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if any number end with the digit 0,it should be divisible by 10, or in other words, it will also be divisible by 2 and 5 as 10=2×5.
prime factorisation of 6^n =(2×3)^n.
here 5 is not in the prime factorisation of 6^n.
hence, for any value of n, 6^n will not be divisible by 5.
therefore, 6^n cannot end with the digit 0 for any natural number n.
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