Question

please do fast it's urgent ​

Answer 1

Answer:

the pic is not clear so send it again I'll ans

Answer 2

Answer:

if any number end with the digit 0,it should be divisible by 10, or in other words, it will also be divisible by 2 and 5 as 10=2×5.

prime factorisation of 6^n =(2×3)^n.

here 5 is not in the prime factorisation of 6^n.

hence, for any value of n, 6^n will not be divisible by 5.

therefore, 6^n cannot end with the digit 0 for any natural number n.