Question

please do fast it's urgent ​

Answer 1

Answer:

Hope this helps. This may satisfy you.

Answer 2

$= > \sin \: a = \frac{3}{4} \\ \\ = > { \sin}^{2}a = \frac{9}{16} \\ \\ = > \sqrt{1 - { \cos }^{2}a } = \frac{9}{16} \\ \\ = > 1 - { \cos}^{2}a = \frac{3}{4} \\ \\ = > \cos \: a = \sqrt{ 1 - \frac{3}{4} } \\ \\ = > \cos \: a = { \frac{ {1} }{2} } \\ \\ tan \: a = \frac{sin \: a}{cos \: a} \\ \\ tan \: a = \frac{3}{4} \times 2 \\ \\ tan \: a \: = \frac{3}{2}$