Question

please do in copy and then send me​

Answer 1

Step-by-step explanation:

$\\ \tt{:}\rightarrowtail \dfrac{x-5}{2}-\dfrac{x-3}{5}=\dfrac{1}{2}$

$\\ \tt{:}\rightarrowtail \dfrac{2(x-5)-5(x-3)}{10}=\dfrac{1}{2}$

$\\ \tt{:}\rightarrowtail \dfrac{2x-10-5x+15}{10}=\dfrac{1}{2}$

$\\ \tt{:}\rightarrowtail \dfrac{2x-5x-10+15}{10}=\dfrac{1}{2}$

$\\ \tt{:}\rightarrowtail \dfrac{-3x+5}{10}=\dfrac{1}{2}$

$\\ \tt{:}\rightarrowtail 2(-3x+5)=10$

$\\ \tt{:}\rightarrowtail -6x+10=10$

$\\ \tt{:}\rightarrowtail -6x=10-10$

$\\ \tt{:}\rightarrowtail -6x=0$

$\\ \tt{:}\rightarrowtail x=\dfrac{0}{-6}$

$\\ \tt{:}\rightarrowtail x=valueless$

Answer 2

Answer:

0/-6

please mark me as brainliest