Question

please do it
2(a+b)²-a(a+b)-5​

Answer 1

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$2 ({a + b})^{2} - a(a + b) - 5 = 0$

$\implies \: 2( {a}^{2} + 2ab + {b}^{2}) - {a}^{2} - ab - 5 = 0$

$\implies \: {2a}^{2} + 2ab + {2b}^{2} - {a}^{2} - ab = 5$

$\implies \: {a }^{2} + ab + {2b}^{2} = 5$

Answer 2

Answer:

a^{2}+b^{2} +3ab -5

Step-by-step explanation:

                                                                           Using Identity-  (a+b)²=a²+2ab+b²                  

$2{(a+b)}^{2} -a(a+b)-5\\\\=>2(a^{2}+2ab +b^{2} ) - a^{2} -ab-5\\\\=>2a^{2} +4ab+b^{2} - a^{2} -ab-5\\\\=>a^{2}+b^{2} +3ab -5$