Math, asked by bpramanik069, 9 months ago

please do it.............​

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Answers

Answered by GangsterTeddy
1

Answer:

I think it would be helpful for you

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Answered by Anshyadav99
0

Answer:

a^3-8/a+3 ÷ (8a^5-16a^4/4a^3+12a^2)

a^3-8/a+3 ÷ (4a^2(2a^3-4a^2)/4a^2(a+3))

a^3-8/a+3 ÷(2a^3-4a^2/a+3)

a^3-8/a+3 × a+3/2a^3-4a^2

a^3-8/2a^3-4a^2

i hope i have simplified the question for you

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