Question

please do it. answer should be correct.( write the property which is used) ​

Answer 1

The sum of interior angles of a pentagon

= (n-2)x180*

=(5-2)180

=3x180

= 540*

<TPQ=180-70

=110* (linear pair)

<PQR=180-60

=120*(linear pair)

•°•540=<TSR+<STP+<TPQ +<PQR+<QRS

540 =30+x+110+120+x (sum of interior angle of a pentagon=540*)

540 =2x+260

2x=540-260

2x=280

x=140*

•°•<STP &<QRS Equals to 140*