please do it fast
and good night.
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Step-by-step explanation:
identity used : x² - y² = (x+y)(x-y)
here x = a²+b²-c² and y = 2ab
=> [a²+b²-c²+2ab][a²+b²-c²-2ab]
=> [ (a+b)² - c²][(a-b)² - c²]
=> (a+b+c)(a+b-c)(a-b+c)(a-b-c)
rishuyadavee06:
thanks
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