Question

please do it for me ​

Answer 1

Answer:

Step-by-step explanation:

αβ

(i)α/β+β/α

Taking LCM We Get,

$=\alpha ^{2} +\beta ^{2} /\alpha \beta\\=((\alpha +\beta )^{2}-2\alpha \beta )/\alpha \beta$

(ii)

$\alpha ^{2}/ \beta +\beta ^{2} /\alpha\\=\alpha ^{3} +\beta ^{3} /\alpha \beta\\a^{3} +b^{3}=(a+b)(a^{2}-ab+b^{2} )\\=(\alpha +\beta )(\alpha ^{2} -\alpha \beta +\beta ^{2} )/\alpha \beta$

Similarly From 1st Question We Know That $\alpha ^{2} +\beta ^{2} =(\alpha+ \beta )^{2}-2\alpha \beta$

We Can Substitute And Solve Further