please do it immediately.a question for experts.
Answers
Assuming the disc to be symmetrical and the density is constant everywhere let's jump into the solution Let the origin be the centre of the bigger disc Then have a negative mass disc of R/3 radius from its centre position find its shadow on the x-axis as well as on the y-axis We can do this as we have angle Given So the x-axis will be =4R/10 And y-axis will be = 3R/10 you can get this by simple trigonometry Now the CENTRE OF MASS EQUATION As we know it's radius is R/3 so the mass of it will be 9 times less than the actual bigger one which comes to just M . For x-axis = 9M(0)-M(4R/10) / 9M-M We get -R/20 For y-axis = 9M(0)-M(3R/10) / 9M-M We get -3R/80 Which seems pretty true as we remove the disc from the initial one we shifts it's com downwards that's why we have negative sign as we account it from the origin