Question

please do it in a copy
$2x - \frac{x + 7}{9} + \frac{x - 5}{3} = \frac{x}{3}$
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Answer 1

Pls mark as brainliest answer

Answer 2

$\sf{\red{\boxed{\huge{Solution}}}}$

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$\sf: \implies\: {\bold{ 2x - \dfrac{x+7}{9} + \dfrac{x-5}{3}= \dfrac{x}{3}}}$

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$\sf: \implies\: {\bold{ \dfrac{9\times 2x - x+7 +3( x - 5) }{9} = \dfrac{x}{3}}}$

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$\sf: \implies\: {\bold{ \dfrac{18x - x+7 +3x - 15 }{9} = \dfrac{x}{3}}}$

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$\sf: \implies\: {\bold{ \dfrac{20x - 8 }{9} = \dfrac{x}{3}}}$

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$\sf: \implies\: {\bold{ 3 ( 20x - 8) = 9x}}$

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$\sf: \implies\: {\bold{ 20x - 8 =\dfrac{9x}{3}}}$

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$\sf: \implies\: {\bold{ 20x - 8 = 3x}}$

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$\sf: \implies\: {\bold{ 17x = 8 }}$

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$\sf: \implies\: {\bold{ x = \dfrac{8}{17}}}$

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