please do it on paper.
question no 11
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here is the answer. hope it helps you brother
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aaina63:
no, you are wrong
then sorry
is it 0 ?
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0
p (x)=x^3+3X^2-5x+4/x-1 x-1=0
x=1
p (1)=(1)^3+3(1)^2-5 (1)+4
=1+3-5+4
=4-1
=3
x=1
p (1)=(1)^3+3(1)^2-5 (1)+4
=1+3-5+4
=4-1
=3
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you are also wrong
now I'm right??
ya, but can you do it on page?
s of course
but like division???
thanks
by long division
okay...
hey... I have done it
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