Math, asked by Anonymous, 1 year ago

Please do it on Ur own.

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Anonymous: Put the value of roots in place of x. then combine both equations. u will get the answers.
Anonymous: Pushkaranmole10 plz answer fast in ans box
Anonymous: someone was writing a answer so I told u here

Answers

Answered by sushant2505
0
mx²+7x+n=0
x=-3
m(-3)²+7(-3)+n=0
9m-21+n=0
9m+n=21 ____(1)
and
x=2/3
m(2/3)²+7(2/3)+n=0
4m/9+14/3+n=0
(4m+42+9n)=0
4m+9n=-42. _____(2)
By solving eq (1) and (2)
we get
m=3
n=-6

Answered by Anonymous
0
Put x = - 3

= m(-3)^2 +7(-3) + n = 0

= 9m - 21 + n = 0

= 9m + n = 21 . 1.

Put x = 2/3

= m(2/3^2) +7(2/3) +n = 0

= 4m/9 + 14/3 + n = 0

= 4m/9 + n = - 14/3 . 2.

Subtract eq 2 from eq1.

= 9m - 4m/9 + n - n = 21-(-14/3)

= 9m - 4m/9 = 21+14/3

= 77m/9 = 77/3

= m = 77/3 * 9/77

= m = 9/3=3.

Put value of m in eq. 1.

= 9*3 + n = 21

= n = 21-27

= - 6.

Hope it's helpful to u.

Anonymous: Bro i did not understand about hw u got the answers
Anonymous: Please edit Ur ans
sushant2505: by solving equation (1) and (2)
Anonymous: And do it on paper clearly and send
Anonymous: Plz
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