Question

please do it properly in a copy with full explanation please do and send fast please​

Answer 1

Answer

u=25m/sec

Distance it travels in 5sec

Distance travelled before the brakes are applied= 25*5=125m

After 5 sec brakes are applied

It then comes to rest in 10sec

u=25m/s

v=0(as it comes to rest)

t=10

a=change in velocity/time=-25/10=-2.5

s=?

s=ut+at^2/2

s=25*10+(-2.5)(100)/2=250-125

The distance it travels after the brakes are applied is 125m

Hope it helps!!