please do it...prove it......
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in this draw a line LET SAY EF parallel to BA THROUGH E
THEN USING CO INTERIOR ANGLES PROPERTY ..YOU WILL GET..
BAE + FEA = WHOLE ANGLE E + DCE
BAE - DCE = WHOLE ANGLE E (FEC)- FEA
BAE - DCE = FEC - FEA = AEC
BAE - DCE = AEC
Hence proved
hope it helps
Please mark this as brainliest
THEN USING CO INTERIOR ANGLES PROPERTY ..YOU WILL GET..
BAE + FEA = WHOLE ANGLE E + DCE
BAE - DCE = WHOLE ANGLE E (FEC)- FEA
BAE - DCE = FEC - FEA = AEC
BAE - DCE = AEC
Hence proved
hope it helps
Please mark this as brainliest
RajSharmaa:
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