Question

please do it quickly ​

Answer 1

$= > \: \: \frac{3 + 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \\ = > \: \: \frac{3 + 2 \sqrt{2} }{3 - 2 \sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{ 3 + 2 \sqrt{2} } \\ \\ = > \: \: \frac{ ( 3 + 2\sqrt{2})^{2} }{ {3}^{2} - {(2 \sqrt{2}) }^{2} } \\ \\ = > \: \: \frac{{(3)}^{2} + {(2 \sqrt{2}) }^{2} + 2 \times 2 \sqrt{2} \times 3}{ 9 - 8 } \\ \\ = > \: \: \frac{9 + 8 + 12\sqrt{2} }{1} \\ \\ = > \: \: 17 + 12\sqrt{2}$

Answer 2

Answer:

$\frac{3 + \sqrt{2} }{3 - \sqrt{2} } \\ = \frac{3 + \sqrt{2} }{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } \\ = \frac{ {(3 + \sqrt{2)} }^{2} }{ {(3 - \sqrt{2)} }(3 + \sqrt{2)} } \\ = \frac{9 + 2 + 2 \times 3 \times \sqrt{2} }{9 - 2} \\ = \frac{11 + 6 \sqrt{2} }{7}$