Math, asked by devpratapyadav, 1 month ago

please do it rightly it is important​

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Answers

Answered by turbojamir
1

Answer:

This problem requires you to rationalize the denominator

Step-by-step explanation:

Here are the steps:

We first multiply both the denominator and numerator of LHS by the conjugate of the denominator.

\frac{(\sqrt{2} +\sqrt{3})(3\sqrt{2}+2\sqrt{3})}{(3\sqrt{2}-2\sqrt{3})(3\sqrt{2}+2\sqrt{3})  }

\frac{ 6+2\sqrt{6} +3\sqrt{6}+6}{ (3\sqrt{2} )^{2}-(2\sqrt{3})^{2} }

\frac{12+5\sqrt{6}}{  18-12}

\frac{12}{6}+\frac{5\sqrt{6} }{6}

2+\frac{5\sqrt{6}}{6}

On comparing this with the RHS we can see that

a = 2 and b = \frac{5}{6}

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