Question

please do it urgently both parts ​

Answer 1

hey your answer is :-

. 3 x-1 = 9. .4 y+2 = 64

= 3x-1 = 3^2. = 4y+2 = 4^3

Now, base are same...

so,

= x - 1 = 2. y + 2 = 3

x = 2 - 1 y = 3 - 2

x = 1. y = 1

Now, question no 6...

9 × 3^x = 27^2x-3

3^2 × 3^ x = 3^3× 2x -3

3^2 + x = 3^3 + 2x - 3

Base are same So...

2 + x = 2x + 3 - 3

2 + x = 2x

2 = 2x - x

2 = x

HENCE,

X = 2...

Answer 2

5. Searching the value of (x):-

3^(x - 1) = 9 ⇒ 3^(x - 1) = 3^2

Now bases are same,

∴ x - 1 = 2 ⇒ x = 3

Now, for (y):-

4^(y + 2) = 64 ⇒ 4^(y + 2) = 4^3

Since bases are same,

∴ y + 2 = 3 ⇒ y = 1

So, x/y = 3/1 or 3.

6. 9 × 3^x = (27)^(2x - 3) ⇒ 3^2 × 3^x = 3^[3(2x - 3)]

Since a^m × a^n = a^(m + n) and, (a^m)^n = a^(mn),

⇒ 3^(x + 2) = 3^(6x - 9)

Since bases are same,

∴ x + 2 = 6x - 9 ⇒ - 5x = - 11 ⇒ x = 11/5.