Math, asked by bb4, 11 months ago

please do my splitting the middle term ​

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Answered by abdul9838
2

 <b> <body bgcolor = "skyblue">

 \small \bf \red{hey \: mate \: here \: is \: ur \: ans} \\  \\ \small \bf \red{ \huge \: solution} \\  \\ \small \bf \red{ {x}^{2} - x - 156 = 0 } \\  \\ \small \bf \red{ {x}^{2} - (13 - 12)x - 156 = 0 } \\  \\ \small \bf \red{ {x}^{2}  - 13x + 12x - 156 = 0} \\  \\ \small \bf \red{x(x - 13) + 12(x - 13) = 0} \\  \\ \small \bf \red{(x + 12)(x - 13) = 0} \\  \\ \small \bf \red{x =  - 12} \\  \\ \small \bf \red{and} \\  \\ \small \bf \red{x = 13} \\  \\ \small \bf \red{2..} \\  \\ \small \bf \red{ {x}^{2} - 32x - 105 = 0 } \\  \\ \small \bf \red{ {x}^{2} - (35 - 3)x - 105 = 0 } \\  \\ \small \bf \red{ {x}^{2}  - 35x + 3x - 105 = 0} \\  \\ \small \bf \red{x(x - 35) + 3(x - 35) = 0} \\  \\ \small \bf \red{(x + 3)( - 35) = 0} \\  \\ \small \bf \red{x =  - 3} \\  \\ \small \bf \red{x = 35 \:  \: ans}

Answered by Sweetbuddy
4
Hey buddy here is ur answer !!!

1) x^2 - x - 156

Solution :

x^2 - 13x + 12x - 156

x (x - 13) 12 (x - 13)

( x + 12 ) ( x - 13 )

→ x = -12

→ x = 13

2) x^2 - 32x - 105

Solution :

x^2 - 35x + 3x - 105

x ( x - 35 ) + 3 ( x - 35 )

( x + 3 ) ( x - 35 )

→ x = - 3

→ x = 35


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