Question

please do not spam or answer nonsense. if answer is correct i will give brainliest

Answer 1

$given \: a + b + c \: \: and \: \frac{1}{a + b} + \frac{1}{b + c} \: \ = \frac{10}{3}$

Multiply both sides (a+b+c)

$= > \frac{a + b + c}{b + c} + \frac{a + b + c}{c + a} + \frac{a + b + c}{a + b} = \frac{10}{7} (a + b + c)$

$= > 1 + \frac{a}{b + c} + 1 + \frac{b}{c + a} + \frac{c}{a + b} = \frac{10 \times 3}{7}$

$= > 3 + \frac{a}{b + c} + \frac{b}{c + a} + \frac{a}{a + b} = \frac{3}{7}$

$= > \frac{a}{b + c} + \frac{b}{c + a} + \frac{c}{a + b} = \frac{30 - 3}{7} = \frac{9}{7}$

Hence the value of given expression is 9\7.

I hope my answer will help u..❤

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