please do on paper............thank you
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cos theta a x/2 + cos theta y/3= theta
cos(3×+2y /6) =theta
squaring both side
cos(3×+2y)^2= (6 theta)^2
cos(9x^2 +12Xy+4y^2)= 36
9x^2cos theta + 12xycos theta 4y^2cost heta = 36 (multiple by sin theta)
answer will come factoring plz
cos(3×+2y /6) =theta
squaring both side
cos(3×+2y)^2= (6 theta)^2
cos(9x^2 +12Xy+4y^2)= 36
9x^2cos theta + 12xycos theta 4y^2cost heta = 36 (multiple by sin theta)
answer will come factoring plz
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