please do questions 27 , 25 , '27 and 28
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yashika15:
please send q 25 and 26
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28. all the three angles measure 130°
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Hello friend
Here goes your answer
27. Consider the triangle ABC
We know that
• Exterior angle=sum of interior opp angles
• Sum of all angles in a triangle is 180°
So angle A + angle B +angle C =180°
Angle 1+2+3=180°
Angle ACD = angle A + angle B = angle 3 + angle 1
Angle ABE = angle A + angle C = angle 3+ angle 2
Angles ACD and ABE are exterior angles
So sum of exterior angles will be Angle ACD + angle ABE
=angle 1+ angle 3+ angle 2+ angle 3
We know that Angle 1+2+3=180°
=180°+ angle 3
Hence it is proved that sum of exterior angles is more than 180°
__________________________________________________
28. Angle 4+ 50° =180° as they form a linear pair
So angle 4=180-50=130°
Angle 4 = angle 1 as they are corresponding angles
Angle 1 = angle 2 as they are corresponding angles
Angle 2 = angle 3 as they are vertically opposite angles
So angle 1=angle 2=angle 3=130°
Hope it helps!!
Here goes your answer
27. Consider the triangle ABC
We know that
• Exterior angle=sum of interior opp angles
• Sum of all angles in a triangle is 180°
So angle A + angle B +angle C =180°
Angle 1+2+3=180°
Angle ACD = angle A + angle B = angle 3 + angle 1
Angle ABE = angle A + angle C = angle 3+ angle 2
Angles ACD and ABE are exterior angles
So sum of exterior angles will be Angle ACD + angle ABE
=angle 1+ angle 3+ angle 2+ angle 3
We know that Angle 1+2+3=180°
=180°+ angle 3
Hence it is proved that sum of exterior angles is more than 180°
__________________________________________________
28. Angle 4+ 50° =180° as they form a linear pair
So angle 4=180-50=130°
Angle 4 = angle 1 as they are corresponding angles
Angle 1 = angle 2 as they are corresponding angles
Angle 2 = angle 3 as they are vertically opposite angles
So angle 1=angle 2=angle 3=130°
Hope it helps!!
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