please do solve provide explaination of the ans.Please.
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komalgautam31:
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on surface electric field is given by
E=kQ/R²
Q=ER²/k
at a distance of R/4 from surface ie at a distance of 5R/4 from the centre of sphere
E'*4πr²=Q/e
E'*4πr²=ER²/ke
E'*4π(5R/4)²=4πeER²/e
E'=16E/25
Answered by
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HEY MATE
YOUR ANWER IS HERE
FOR ELECTRIC FIELD AT A DISTANCE R IS E= KQ/R^2
WHEN R BECOMES R/4
E' = KQ/(R/4)^2
SO IT BECOMES 16 TIMES TO THE ORIGINAL ONE SO ANSWER IS D
E' = 16E
HOPE IT HELPS YOU
PLEASE MARK IT BRAINLIEST IF FOUND APPROPRIATE
THANK YOU
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