Question

please do the 7 one....................

Answer 1

Hi!

Since the length and breadth of the park are in the ratio 2:1, let the breadth be a and the length be 2a.

Perimeter of the park = 2 (a + 2a) = 2 × 3a = 6a

According to question

 6a = 240 m

a = 240/6 m = 40 m

So, breadth = 40 m and length = 2 × 40 m = 80 m

Area of the park = 80 × 40 m2 = 3200 m2

 

Since the path of wide 2 m runs around the boundary inside the park, length and breadth of the park excluding the path get decreased by 4 m (= 2 m + 2 m)

 

Length of the park excluding the path = (80 – 4) m = 76 m

Breadth of the park excluding the path = (40 – 4) m = 36 m

Area of the park excluding the path = 76 × 36 m2 = 2736 m2

 

Thus, area of the path = Area of the park – Area of the park excluding the path

= (3200 – 2736) m2 = 464 m2

 

The cost of constructing the path can be found the multiplying the area of the path with the given rate.

 

Cheers!

Answer 2

Let the length and breath be 2x and x

Perimeter=2(l+b)

2(x+2x)=240

6x=240

x=240/6=40

l=40*2=80

b=40