Please do the above question. Question no.6a
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Answered by
1
x^2 + 2ax+p=(x+b)^2
x^2+2ax+p=x^2+2bx+b^2
compare
u get
a=b
p=b^2
therefore p=a^2
x^2+2ax+p=x^2+2bx+b^2
compare
u get
a=b
p=b^2
therefore p=a^2
Answered by
2
Heya !!!
This is your answer.....
QUESTION :::----
If x^2 + 2ax + p = (x+b)^2, then find the relation between a and p.
SOLUTION :::----
x^2 + 2ax + p = (x+b)^2
x^2 + 2ax + p = x^2 + 2bx + b^2.
2ax + p = 2bx + b^2.
By comparing both sides.....
We can say that......
a = b, and
p = b^2.
Just interchange......
b = a.... and
b = SQ (p). ......(SQ = Square root).
As b = b...
So...
a = SQ (p).
or
p = a^2.
Hence the relation between a and p is a^2 = p.
Hope it helpssss.....
This is your answer.....
QUESTION :::----
If x^2 + 2ax + p = (x+b)^2, then find the relation between a and p.
SOLUTION :::----
x^2 + 2ax + p = (x+b)^2
x^2 + 2ax + p = x^2 + 2bx + b^2.
2ax + p = 2bx + b^2.
By comparing both sides.....
We can say that......
a = b, and
p = b^2.
Just interchange......
b = a.... and
b = SQ (p). ......(SQ = Square root).
As b = b...
So...
a = SQ (p).
or
p = a^2.
Hence the relation between a and p is a^2 = p.
Hope it helpssss.....
Sid000:
You are the best! !!
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