Question

please do the sums as mentioned below 9TH STD

Answer 1

Step-by-step explanation:

(1)=f(-1/3)=3(-1/3)+1 =-1+1=0

2) f(1)=(1)²-1=0

f(-1)=(-1)²-1=0

3) g(2/root3)=3(2/root3)²-2=3(4/3)-2=4-2=2

4) p(x)=(1)³-6(1)²+11(1)-6

=1-6+5=0

5) f(x)=5x-pi

f(4/5)=4-pi

6) f(x)=x²

f(0)=(0)²=0

7) f(-m/l)=l(-m/l)+m

=0

8) f(x)=2x+1

f(1/2)=2(1/2)+1=2

OK friend this is urs answer

Answer 2

Answer:

1. i f(x) = 3x+1, x= 1/3

=

f (x) = I/3

f(I/3) = 3 (I/3) + 1

f (1/3) = 1 + 1

= 2