Question

please do these number

Answer 1

first of all you can check in mind or in rough that after putting X = 2, the equation becomes zero
You can say F(x) at x = 2 satisfies the equation.
so (x -2) is a factor of the equation.
now divide this cubic polynomial by x - 2 and get a quadratic equation as the quotient.
now let the quotient be of the form ax²-bx+c.
then we can write the given question or the given cubic polynomial as:

F(x) = (x-2) (ax²-bx+c) = 0

{now take this quadratic and linear form and then find the value of x}

[hope this helps, and you can easily solve and find from the quadratic equation, by separating it in two linear forms.]

Answer 2

The answer for your question is above