Question

Please do this..........

Answer 1

Answer:

plz telll the answer of 1st

Answer 2

Explanation:

1)) y = e^(ax) x sin(Bx)

differentiation wrt x

dy /dx = d/dx( e^(ax) x sin(Bx) )

we know, if y = u. v , then dy/dx = u. (dv/dx) + v. ( du/dx)

=)) e^(ax) ( d/dx(sin (Bx))

+ sin(Bx)(d/dx ( e^(ax)) )

=)) e^(ax) x cos (Bx) x d/dx(Bx)

+ sin(Bx) ( e^(ax)) x d/dx(ax)

=)) e^(ax) x cos(Bx) x B

+ sin(Bx) (e^(ax) x (x )

dy/dx

= e^(ax) (B cos(Bx)

+ (x) sin(Bx))

____________________________

Another function is,

2)) y = tan ( π/4 + x/2 )

Differentiation wrt x

dy/dx = d/dx(tan (π/4 + x/2 ))

= )) sec² (π/4 + x/2 ) x (d/dx(π/4 + x/2)

= )) sec² (π/4 + x/2 ) x ( 0 + 1/2 )

= )) sec² (π/4 + x/2 ) (1/2 )

= ))( 1/2 ) (sec² (π/4 + x/2 ))

dy/dx

= ( 1/2 ) (sec² (π/4 + x/2 ))