Question

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An object 4.0 CM in size , is placed at two 25.0 CM in front of a concave mirror of focal length 15 cm. at what distance from the mirror should a screen we placed in order to obtain a sharp image ? find the nature and the size of the image ​

Answer 1

Answer=

Height of the Object(H₀) = 4 cm.

Object Distance(u) = 25 cm.(negative)

Focal Length = 15 cm.(negative)

Using the Mirror's Formula,

   

⇒  

⇒  v = - 37.5 cm.

Thus, the image is formed behind the mirror. Since the Distance is Negative, thus the Image is Real.

Thus, Screen is to be placed at a Distance of 37.5 cm behind the Mirror.

Now, Magnification = H₁/H₀

Also, Magnification = -v/u

  ∴ H₁/H₀ = -v/u

⇒ H₁/4 = - (-37.5)/25

⇒ H₁ = 37.5 × 4/25

⇒ H₁ = 150/25

⇒ H₁ = 6 cm.

Since, the Size of the Image is greater than the size of the Object, thus the image is Magnified.

Hence, Characteristics of the Images are---

Real, Inverted and Magnified.

Answer 2

Answer:

Hight of object 4cm(H0)

distance of object 25cm(-)

focal length 15cm(-)