Question

please do this correctly.​

Answer 1

Answer:

Show that [1/loga (abc)] + [1/logb (abc)] + [1/logc (abc)] = 1

My working:

[1/log abc/log a] + [1/log abc/log b] + [1/log abc/log c]

=[log a/log abc] + [log b/log abc] + [log c/log abc]

=[log (a*b*c)] / [log (abc)^3]

=log (abc) / log (abc)^3

=1/3