please do this
factorise 4a^2-9b^3
Answers
Answered by
12
hay user here is ur answer
Consider 4a2 - 9b2 - 2a - 3b
= (2a)2 – (3b)2 – 2a – 3b
= (2a – 3b)(2a + 3b) – 1(2a + 3b)
= (2a + 3b)[(2a – 3b) – 1]
= (2a + 3b)[2a – 3b –1]
Consider 4a2 - 9b2 - 2a - 3b
= (2a)2 – (3b)2 – 2a – 3b
= (2a – 3b)(2a + 3b) – 1(2a + 3b)
= (2a + 3b)[(2a – 3b) – 1]
= (2a + 3b)[2a – 3b –1]
Similar questions