Question

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A car of mass 1250kg is moving with uniform speed of 72kmph . On applying brakes it's speed plus reduced to 18kmph. Calculate initial and final kinetic energy and find change in kinetic energy

Answer 1

Initial Kinetic energy(I. K. E) = mu²
=1250 × (72×5/18)J. (we have to change it in S. I unit)
=1250 × 15 = 18570J.

Similarly,
Final Kinetic energy(F. K. E) = mv²
= 1250 × (18×5/18)J
= 1250×5= 6250J.


Change in K. E = F. K. E - I. K. E = 18570-6250=12320J.


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