Question

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Answer 1

Answer:

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Answer 2

Answer:

Answer:

• The angle of B=65°
• Area of a triangle,∆=54cm²

Given:

1. In ∆ABC,AB=5cm, AC=5cm and A°=50°.
2. The area of the triangle with sides 9cm, 12cm and 15cm.

Solution:

→ Since,AB=5cm

AC=5cm and A°=50°

Sum of angles in a triangle=180°

$50 + x + x = 180$

$50 + 2x = 180$

$2x = 130$

$x = \frac{130}{2} = 65$

So, The angle of B is 65°.

Now

→ Given sides are,

$a = 12cm$

$b = 15cm$

$c = 9cm$

As we know that,

$s = \frac{a + b + c}{2}$

$s = \frac{12 + 15 + 9}{2}$

$s = \frac{36}{2} = 18$

So,

Area of the triangle,

∆=√s(s-a)(s-b)(s-c)

∆=√18(9)(6)(3)

∆=√18×18×3×3

∆=18×3

∆=54cm²

So, The area of a triangle=54cm².