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THE HEIGHT OF A PARALLELOGRAM IS ONE THIRD ITS BASE. IF THE AREA OF THE PARALLELOGRAM IS 108 CMSQUARE, FIND ITS BASE AND HEIGHT
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Height of parallelogram=x
Base of the parallelogram=3x
area of IIgm=(3x)(x)
(3x^2)=108
x^2 = 36
x = 6 cm =Height
Base =3(6cm)=18cm
Base of the parallelogram=3x
area of IIgm=(3x)(x)
(3x^2)=108
x^2 = 36
x = 6 cm =Height
Base =3(6cm)=18cm
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